Advertisements
Advertisements
प्रश्न
Factorise: 75(x + y)2 - 48(x - y)2
योग
Advertisements
उत्तर
75(x + y)2 - 48(x - y)2
= 3[25 (x + y)2 - 16 (x - y)2]
= 3[{5 (x + y)2} - {4 (x - y)}2]
Using a2 – b2 = (a + b) (a – b)
= 3 [5(x + y) + 4(x - y)] [5(x + y) - 4(x - y)]
= 3 [5x + 5y + 4x - 4y] [5x + 5y - 4x + 4y]
= 3 (9x + y) (x + 9y)
shaalaa.com
Factorisation by Difference of Two Squares
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Factorise: 1 - 100a2
Factorise: (a+ 2b)2 - a2
Factorise: (5a - 3b)2 - 16b2
Factorise: `(7 3/10)^2 - (2 1/10)^2`
Factorise: a2 - b2 - 2b - 1
factorise : 25(2x - y)2 - 16(x - 2y)2
Factorise: `9x^2 - 1/16`
Factorise: (a - 3b)2 - 36 b2
Factorise: 25(a - 5b)2 - 4(a - 3b)2
Factorise a2b − b3. Using this result, find the value of 1012 × 100 − 1003.
