Advertisements
Advertisements
प्रश्न
Factorise:
4x2 + 9y2 + 16z2 + 12xy – 24yz – 16xz
Advertisements
उत्तर
It is known that,
(x + y + z)2 = x2 + y2 + z2 + 2xy + 2yz + 2zx
4x2 + 9y2 + 16z2 + 12xy – 24yz – 16xz
= (2x)2 + (3y)2 + (−4z)2 + 2(2x)(3y) + 2(3y)(−4z) + 2(−4z)(2x)
= (2x + 3y – 4z)2
= (2x + 3y – 4z)(2x + 3y – 4z)
APPEARS IN
संबंधित प्रश्न
Expand the following, using suitable identity:
(3a – 7b – c)2
Factorise the following:
`27p^3-1/216-9/2p^2+1/4p`
Factorise the following:
27y3 + 125z3
If 9x2 + 25y2 = 181 and xy = −6, find the value of 3x + 5y
Simplify `(x^2 + y^2 - z)^2 - (x^2 - y^2 + z^2)^2`
Simplify (2x + p - c)2 - (2x - p + c)2
If a + b + c = 0 and a2 + b2 + c2 = 16, find the value of ab + bc + ca.
Find the value of 4x2 + y2 + 25z2 + 4xy − 10yz − 20zx when x = 4, y = 3 and z = 2.
If \[x - \frac{1}{x} = - 1\] find the value of \[x^2 + \frac{1}{x^2}\]
Find the cube of the following binomials expression :
\[2x + \frac{3}{x}\]
Evaluate of the following:
463+343
If \[x + \frac{1}{x} = 3\], calculate \[x^2 + \frac{1}{x^2}, x^3 + \frac{1}{x^3}\] and \[x^4 + \frac{1}{x^4}\]
If a − b = 5 and ab = 12, find the value of a2 + b2
(a − b)3 + (b − c)3 + (c − a)3 =
If a + b + c = 9 and ab + bc + ca =23, then a3 + b3 + c3 − 3abc =
Use the direct method to evaluate the following products:
(x + 8)(x + 3)
Use the direct method to evaluate :
(3b−1) (3b+1)
Simplify by using formula :
`("a" + 2/"a" - 1) ("a" - 2/"a" - 1)`
If a2 - 3a - 1 = 0 and a ≠ 0, find : `"a" + (1)/"a"`
If `"p" + (1)/"p" = 6`; find : `"p"^4 + (1)/"p"^4`
