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प्रश्न
Factorise : 2x3 + 54y3 - 4x - 12y
योग
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उत्तर
2x3 + 54y3 - 4x - 12y
= 2 ( x3 + 27y3 - 2x - 6y )
= 2 [ { (x)3+ (3y)3} - 2(x + 3y) ]
[ Using identity (a3 + b3) = (a + b)(a2 - ab + b2) ]
= 2[ {(x + 3y)(x2 - 3xy + 9y2)} - 2(x + 3y) ]
= 2(x + 3y)(x2 - 3xy + 9y2 - 2)
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Method of Factorisation : the Sum Or Difference of Two Cubes
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