Advertisements
Advertisements
प्रश्न
Factorise : 2x3 + 54y3 - 4x - 12y
बेरीज
Advertisements
उत्तर
2x3 + 54y3 - 4x - 12y
= 2 ( x3 + 27y3 - 2x - 6y )
= 2 [ { (x)3+ (3y)3} - 2(x + 3y) ]
[ Using identity (a3 + b3) = (a + b)(a2 - ab + b2) ]
= 2[ {(x + 3y)(x2 - 3xy + 9y2)} - 2(x + 3y) ]
= 2(x + 3y)(x2 - 3xy + 9y2 - 2)
shaalaa.com
Method of Factorisation : the Sum Or Difference of Two Cubes
या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
APPEARS IN
संबंधित प्रश्न
Factorise : 64 - a3b3
Factorise : a6 + 27b3
Factorise : 3x7y - 81x4y4
Factorise : a3 + 0.064
Factorise:
a4 - 343a
Factorise:
`(8"a"^3)/27 - "b"^3/8`
Factorise:
a6 – b6
Factorise : 1029 - 3x3
Factorise : a6 - 7a3 - 8
Evaluate :
`[ 5.67 xx 5.67 xx 5.67 + 4.33 xx 4.33 xx 4.33 ]/[5.67 xx 5.67 - 5.67 xx 4.33 + 4.33 xx 4.33]`
