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External dimensions of a closed wooden box are in the ratio 5:4:3. If the cost of painting its outer surface at the rate of Rs 5 per dm2 is Rs 11,750, find the dimensions of the box. - Mathematics

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प्रश्न

External dimensions of a closed wooden box are in the ratio 5:4:3. If the cost of painting its outer surface at the rate of Rs 5 per dm2 is Rs 11,750, find the dimensions of the box.

योग
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उत्तर

External dimensions of a closed wooden box are in the ratio 5:4:3.

Let the external dimensions of the closed wooden box be 5x, 4x and 3x.

The cost of painting = ₹ 5 per dm2

Total cost of painting = ₹ 11750

∴ Total surface area = `"Total cost of painting"/("Cost of painting per dm"^2) = 11750/5`

Total surface area of a cuboid = 2(lb + bh + hl)

= 2(5x × 4x + 4x × 3x + 3x × 5x)

= 2(20x2 + 12x2 + 15x2)

= 2 × 47x2

= 94x2

Since, total surface area = 2350 dm2

⇒ 94x2 = 2350

⇒ `x^2 = 2350/94 = 25`

∴ x = 5

Hence, dimensions of the box are 5x × 5 = 25 dm, 4x × 5 = 20 dm and 3x × 5 = 15 dm.

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अध्याय 11: Mensuration - Exercise [पृष्ठ ३५८]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 8
अध्याय 11 Mensuration
Exercise | Q 109. | पृष्ठ ३५८

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