Question

The dimensions of an oil tin are 26 cm × 26 cm × 45 cm. Find the area of the tin sheet required for making 20 such tins. If 1 square metre of the tin sheet costs Rs 10, find the cost of tin sheet used for these 20 tins.

Answer 1

\[\text{ Dimensions of the oil tin are 26 cm } \times 26 cm \times 45 cm . \]

\[\text { So, the area of tin sheet required to make one tin  }= 2 \times (\text { length }\times \text { breadth + breadth } \times \text { height + length } \times \text { height) }\]

\[ = 2 \times (26 \times 26 + 26 \times 45 + 26 \times 45)\]

\[ = 2 \times (676 + 1170 + 1170) = 6032 {cm}^2 \]

\[\text { Now, area of the tin sheet required to make 20 such tins = 20 }\times \text { surface area of one tin }\]

\[ = 20 \times 6032\]

\[ = 120640 {cm}^2 \]

\[\text { It can be observed that 120640 } {cm}^2 = 120640 \times 1cm \times 1cm \]

\[ = 120640 \times \frac{1}{100}m \times \frac{1}{100}m ( \because 100 cm = 1 m)\]

\[ = 12 . 0640 m^2 \]

\[\text { Also, it is given that the cost of 1 } m^2 \text { of tin sheet = Rs 10 } \]

\[ \therefore\text {  The cost of 12 . 0640 m^2 of tin sheet = 12 . 0640 } \times 10 =\text {  Rs  }120 . 6\]