Advertisements
Advertisements
प्रश्न
Express (sin 67° + cos 75°) in terms of trigonometric ratios of the angle between 0° and 45°.
Advertisements
उत्तर
(sin 67° + cos 75°)
= (sin (90°−23°) + cos (90°−15°)) .....(∵ sin(90°−θ) = cosθ and cos(90°−θ) = sinθ)
= (cos 23°+ sin 15°)
संबंधित प्रश्न
Without using trigonometric tables evaluate
`(sin 35^@ cos 55^@ + cos 35^@ sin 55^@)/(cosec^2 10^@ - tan^2 80^@)`
(i)` (1-cos^2 theta )cosec^2theta = 1`
Prove that:
`(sin^2θ)/(cosθ) + cosθ = secθ`
Write True' or False' and justify your answer the following :
The value of \[\sin \theta\] is \[x + \frac{1}{x}\] where 'x' is a positive real number .
2 (sin6 θ + cos6 θ) − 3 (sin4 θ + cos4 θ) is equal to
9 sec2 A − 9 tan2 A is equal to
If sin θ = `1/2`, then find the value of θ.
Prove that `(sin^2θ)/(cos θ) + cos θ = sec θ`.
If tan θ = 3, then `(4 sin theta - cos theta)/(4 sin theta + cos theta)` is equal to ______.
If tan θ + sec θ = l, then prove that sec θ = `(l^2 + 1)/(2l)`.
