Question

Which term of the A.P. −4, −1, 2, ... is 101?

Answer 1

We have been given an arithmetic progression where
a = −4, d = −1− (−4) =3 and a_n = 101
We need to find which term of the given AP is 101 so, we need to find n.
Using a_n = a + (n − 1)d
Substituting the values in the formula we get
101 = −4 + (n−1)3
101+ 7 = 3n
3n =108
n =36
Therefore, 36th term of given A.P is 101.