Question

Express erg in terms of mass, length and time.

Answer 1

Since

\[1\ \text{erg} = 1\ \text{dyne} \times 1\ \text{cm}\]

and

\[1\ \text{dyne} = 1\ \text{g cm s}^{-2}\]

\[{1\ \text{erg} = 1\ \text{g cm}^{2}\ \text{s}^{-2}}\]