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प्रश्न
Express 121 as the sum of 11 odd numbers.
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उत्तर
We know that the sum of first n odd natural numbers is n2.
121 = (11)2
Therefore, 121 is the sum of the first 11 odd natural numbers.
121 = 1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21
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संबंधित प्रश्न
Using the given pattern, find the missing numbers.
12 + 22 + 22 = 32
22 + 32 + 62 = 72
32 + 42 + 122 = 132
42 + 52 + _ 2 = 212
52 + _ 2 + 302 = 312
62 + 72 + _ 2 = __2
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To find pattern:
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Without adding find the sum:
1 + 3 + 5 + 7 + 9
Without adding, find the sum:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19
Without adding, find the sum:
1 + 3 + 5 + 7 + 9 + 11 + 13 + 15 + 17 + 19 + 21 + 23
How many numbers lie between squares of the given numbers?
12 and 13
64 is the square number of __________
Fill in the blank box.
The sum of first six odd natural numbers is ______.
The sum of first n odd natural numbers is n2.
The perimeters of two squares are 40 and 96 metres respectively. Find the perimeter of another square equal in area to the sum of the first two squares.
