Advertisements
Advertisements
प्रश्न
Explain the working of the transformer.
Advertisements
उत्तर
Principle:
The principle of a transformer is the mutual induction between two coils. That is, when an electric current passing through a coil changes with time, an emf is induced in the neighbouring coil.
Working:
- If the primary coil is connected to a source of alternating voltage, an alternating magnetic flux is set up in the laminated core.
- If there is no magnetic flux leakage, then the whole magnetic flux linked with primary coil is also linked with the secondary coif This means that rate at which magnetic flux changes through each turn is same for both primary and secondary coils.
- As a result of flux change, emf is induced in both primary and secondary coils. The emf induced in the primary coil εp is almost equal and opposite to the applied voltage υp and is given by
υp = εp = -Np `("d" Φ_"B")/"dt"` .....(1) - The frequency of alternating magnetic flux in the core is the same as the frequency of the applied voltage. Therefore, induced emf in secondary will also have the same frequency as that of applied voltage.
- The emf induced in the secondary coil eg is given by
εs = -Ns `("d" Φ_"B")/"dt"`
where Np and Ns are the number of turns in the primary and secondary coil, respectively. If the secondary circuit is open, then εs = υs where υs is the voltage across secondary coil.
υs εs = -Ns `("d" Φ_"B")/"dt"` .....(2)
From equation (1) and (2),
`"v"_"s"/epsilon_"s" = "N"_"s"/"N"_"p"` = K ....(3)
This constant K is known as voltage transformation ratio. For an ideal transformer,
Input power υp ip = Output power υsis
where iυp and is are the currents in the primary and secondary coil respectively. Therefore,
`"v"_"s"/"v"_"p" = "N"_"s"/"N"_"p" = "i"_"p"/"i"_"s"`
Equation (4) is written in terms of amplitude of corresponding quantities,
`"V"_"s"/"V"_"p" = "N"_"s"/"N"_"p" = "I"_"p"/"I"_"s"` = K ....(4)
(i) If Ns > Np ( or K > 1)
∴ Vs > Vp and Is < Ip.
This is the case of a step-up transformer in which voltage is decreased and the corresponding current is decreased.(ii) If Ns < Np (or K < 1)
∴ Vs < Vp and Is > Ip
This is a step-down transformer where voltage is decreased and the current is increased.
APPEARS IN
संबंधित प्रश्न
State the principle of the step-down transformer and its working.
Complete the following sentence :
……… energy is converted into …………energy by an electric motor.
The following diagram in Fig. 10.44 shows a coil X connected to a sensitive centre –zero galvanometer G and a coil P connected to a battery through a switch S.

(a) Describe the observation when the switch S is (i) closed suddenly, (ii) then kept closed, (iii) finally opened.
(b) Name and state the law which explains the above observations.
A transformer is designed to work from a 240 V a.c. mains and to give a supply of 8 V to ring a house bell. The primary coil has 4800 turns. How many turns will be in the secondary coil?
State the principle of a step-up transformer. Explain, with the help of a labeled diagram, its working ?
The primary coil of a transformer has 800 turns and the secondary coil has 8 turns. It is connected to a 220 V ac supply. What will be the output voltage?
For an LCR circuit, the power transferred from the driving source to the driven oscillator is P = I2Z cos φ.
- Here, the power factor cos φ ≥ 0, P ≥ 0.
- The driving force can give no energy to the oscillator (P = 0) in some cases.
- The driving force cannot syphon out (P < 0) the energy out of oscillator.
- The driving force can take away energy out of the oscillator.
A 60 W load is connected to the secondary of a transformer whose primary draws line voltage. If a current of 0.54 A flows in the load, what is the current in the primary coil? Comment on the type of transformer being used.
An iron rod is placed parallel to magnetic field of intensity 2000 Am-1. The magnetic flux through the rod is 6 × 10−4 Wb and its cross-sectional area is 3 cm2. The magnetic permeability of the rod in Wb A-1m-1 is ______.
