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Explain the Structure of Hydronium Ion. - Chemistry

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प्रश्न

Explain the structure of Hydronium ion.

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उत्तर

Structure of hydronium ion: Hydronium ions (H3O+) are formed when a hydrogen ion released from acid combines with water molecules.
Oxygen atom in water molecule attains an octet by forming two single covalent bonds with two hydrogen atoms but it still contains two lone pairs of electrons.
H3O+ is formed when the oxygen atom in water molecule donates a lone pair of electrons to a hydrogen ion thus establishing a coordinate bond between the oxygen atom and the hydrogen ion.

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अध्याय 2: Chemical Bonding - Exercise 2 [पृष्ठ ४३]

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फ्रैंक Chemistry Part 2 [English] Class 10 ICSE
अध्याय 2 Chemical Bonding
Exercise 2 | Q 10.1 | पृष्ठ ४३

संबंधित प्रश्न

Choose the most appropriate answer from the following list of oxides which fit the description.

A covalent oxide of a metalloid.


Name the following:

The property of element by virtue of which atoms of the element can link to each other in the form of a long chain or ring structure.


What type of bonds are present in water molecule? Draw the electron-dot structure of water (H2O).


will CCl4 conduct electricity or not?

give reason for your choice.


Draw the electron-dot structure of N2 and state the type of bonding. 


You can buy solid air-freshners in shops. Do you think these substance are ionic or covalent? Why?


Give examples for the following:
Two gaseous polar compounds.


Carbon forms four covalent bonds by sharing its four valence electrons with four univalent atoms, e.g., hydrogen. After the formation of four bonds, carbon attains the electronic configuration of ______.


Which of the following are correct structural isomers of butane?

  1. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\phantom{....}|\phantom{....}|\\
    \ce{H - C - C - C - C - H}\\
    |\phantom{....}|\phantom{....}|\phantom{....}|\\
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    \end{array}\]

  2. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\phantom{....}|\\
    \ce{H - C - C - C - H}\\
    |\phantom{.....}|\phantom{.....}|\\
    \ce{H}\ce{H-C-H}\ce{H}\\
    |\\
    \ce{H}\\
    \end{array}\]
  3. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\phantom{....}|\\
    \ce{H - C - C - C - H}\\
    |\phantom{.....}\backslash\phantom{..}|\\
    \phantom{....}\ce{H}\phantom{......}\ce{C - H}\phantom{}\\
    \phantom{.......}|\\
    \phantom{.......}\ce{H}\\
    \end{array}\]
  4. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\\
    \ce{H - C - C - H}\\
    |\phantom{....}|\\
    \ce{H - C - C - H}\\
    |\phantom{....}|\\
    \ce{H}\phantom{...}\ce{H}\\
    \end{array}\]

State the reasons, why carbon cannot

  1. Lose four electrons to form C4+ cation and
  2. Gain four electrons to form C4- anion.

How does carbon overcome this problem to form compounds?


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