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प्रश्न
Expand the following:
(x – 3y)3
योग
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उत्तर
Given: Expand (x – 3y)3
Step-wise calculation:
Using the formula for the cube of a binomial:
(a – b)3 = a3 – 3a2b + 3ab2 – b3
Here, a = x and b = 3y.
So, (x – 3y)3 = x3 – 3x2(3y) + 3x(3y)2 – (3y)3
Calculate each term:
= x3 – 9x2y + 27xy2 – 27y3
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क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Expansions - Exercise 3A [पृष्ठ ६४]
