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प्रश्न
Expand the following:
`(3x - 1/x)^3`
योग
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उत्तर
Given: `(3x - 1/x)^3`
Step-wise calculation using the binomial expansion formula for (a – b)3 = a3 – 3a2b + 3ab2 – b3:
1. Here, `a = 3x` and `b = 1/x`.
2. Compute each term:
a3 = (3x)3 = 27x3
`3a^2b = 3 xx (3x)^2 xx 1/x`
`3a^2b = 3 xx 9x^2 xx 1/x`
3a2b = 27x
`3ab^2 = 3 xx 3x xx (1/x)^2`
`3ab^2 = 3 xx 3x xx 1/x^2`
`3ab^2 = 9/x`
`b^3 = (1/x)^3`
`b^3 = 1/x^3`
3. Substitute these into the expansion formula with correct signs (note the minus signs alternate):
`(3x - 1/x)^3 = a^3 - 3a^2b + 3ab^2 - b^3`
`(3x - 1/x)^3 = 27x^3 - 27x + 9/x - 1/x^3`
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अध्याय 3: Expansions - Exercise 3A [पृष्ठ ६४]
