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Examine whether the function is continuous at the points indicated against them:f(x) = x3 − 2x + 1, for x ≤ 2 = 3x − 2, for x > 2, at x = 2

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प्रश्न

Examine whether the function is continuous at the points indicated against them:
f(x) = x3 − 2x + 1,         for x ≤ 2
      = 3x − 2,                 for x > 2, at x = 2

योग
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उत्तर

`lim_(x→2^-) "f"(x) = lim_(x→2^-) (x^3 - 2x + 1)`
= (2)3 − 2(2) + 1 = 5
`lim_(x→2^+) "f"(x) = lim_(x→2^+) (3x - 2)`
= 3(2) − 2 = 4
∴ `lim_(x→2^-) "f"(x) ≠ lim_(x→2^+) "f"(x)`
∴ Function f is discontinuous at x = 2

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Continuity - Exercise 8.1 [पृष्ठ १११]

APPEARS IN

बालभारती Mathematics and Statistics (Commerce) Part 1 [English] Standard 11 Maharashtra State Board
अध्याय 8 Continuity
Exercise 8.1 | Q 2. (i) | पृष्ठ १११

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