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प्रश्न
Evaluate `int (cos 2x + 2sin^2x)/(cos^2x) dx`
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उत्तर
`(cos 2x + 2sin^2x)/(cos^2x)`
`= (cos 2x + (1-cos 2x))/cos^2x` [`cos 2x = 1 - sin^2 x`]
`= 1/cos^2x`
`= sec^2 x`
`:. int (cos^2x + 2sin^2x)/cos^2x` dx = `int sec^2 x dx = tanx + C`
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