हिंदी

Draw the Circumcircle of δPmt in Which Pm = 5.6 Cm, ∠P = 60°, ∠M = 70°.

Advertisements
Advertisements

प्रश्न

Draw the circumcircle of ΔPMT in which PM = 5.6 cm, ∠P = 60°, ∠M = 70°.

योग
Advertisements

उत्तर

Step-1: construct the segment PM having length 5.6 cm and using protractor draw lines at the angles P and M which measures 60° and 70° respectively mark the intersection point as T thus ∆PMT is ready

Step-2: construct the perpendicular bisector of line PM by keeping the needle of compass at point P and taking approximately more than half of PM distance in compass draw arc above and below PM

Step-3: keeping the same measurement in compass keep the needle at point M and draw intersecting arcs above and below segment PM

Step-4: join the intersections of arcs to get a line ‘a’ which is the perpendicular bisector of segment PM.

Step-5: Similarly by repeating steps 3,4,5 construct a perpendicular bisector for line TM so instead of P substitute T and repeat steps 3,4,5 we will get a line ‘b’ perpendicular bisector of segment TM

Step-6: keep the needle of compass at point of intersection of the line a and b and from there take distance till any vertex of triangle PTM and construct the circle

The circle is required circumcircle to ∆PTM

shaalaa.com
Property of an Angle Bisector of a Triangle
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2016-2017 (July)

APPEARS IN

संबंधित प्रश्न

Given below is the triangle and length of line segments. Identify in the given figure, ray PM is the bisector of ∠QPR.


Given below is the triangle and length of line segments. Identify in the given figure, ray PM is the bisector of ∠QPR.


Measures of some angles in the figure are given. Prove that `"AP"/"PB" = "AQ"/"QC"`.


Find QP using given information in the figure.


In the given fig, bisectors of ∠B and ∠C of ∆ABC intersect each other in point X. Line AX intersects side BC in point Y. AB = 5, AC = 4, BC = 6 then find `"AX"/"XY"`.


In ▢ABCD, seg AD || seg BC. Diagonal AC and diagonal BD intersect each other in point P. Then show that `"AP"/"PD" = "PC"/"BP"`.


In Δ ABC and Δ PQR,
∠ ABC ≅ ∠ PQR, seg BD and
seg QS are angle bisector.
`If  (l(AD))/(l(PS)) = (l(DC))/(l(SR))`
Prove that : Δ ABC ∼ Δ PQR


Seg NQ is the bisector of ∠ N
of Δ MNP. If MN= 5, PN =7,
MQ = 2.5 then find QP.


In ΔABC, ∠ACB = 90°. seg CD ⊥ side AB and seg CE is angle bisector of ∠ACB.

Prove that: `(AD)/(BD) = (AE^2)/(BE^2)`.


In the figure, ray YM is the bisector of ∠XYZ, where seg XY ≅ seg YZ, find the relation between XM and MZ. 


Draw seg AB = 6.8 cm and draw perpendicular bisector of it. 


In the following figure, ray PT is the bisector of QPR Find the value of x and perimeter of QPR.


From the information given in the figure, determine whether MP is the bisector of ∠KMN.


If ΔABC ∼ ΔDEF such that ∠A = 92° and ∠B = 40°, then ∠F = ?


In ΔABC, ray BD bisects ∠ABC, A – D – C, seg DE || side BC, A – E – B, then for showing `("AB")/("BC") = ("AE")/("EB")`, complete the following activity:

Proof :

In ΔABC, ray BD bisects ∠B.

∴ `square/("BC") = ("AD")/("DC")`   ...(I) (`square`)

ΔABC, DE || BC

∴ `(square)/("EB") = ("AD")/("DC")`   ...(II) (`square`)

∴ `("AB")/square = square/("EB")`   ...[from (I) and (II)]


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×