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Draw an Electron Dot Diagram to Show the Formation of the Following Compound. - Chemistry

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प्रश्न

Draw an electron dot diagram to show the formation of the following compound.
Magnesium chloride [ H=1, C=6, Mg=12, Cl=17].

आकृति
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उत्तर

Electron dot structure of magnesium chloride:

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अध्याय 2: Chemical Bonding - Exercise 7 [पृष्ठ ४८]

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फ्रैंक Chemistry Part 2 [English] Class 10 ICSE
अध्याय 2 Chemical Bonding
Exercise 7 | Q 8.2 | पृष्ठ ४८

संबंधित प्रश्न

Why covalent compounds are different from ionic compounds?


 Why are most carbon compounds poor conductors of electricity?


 Explain the formation of a chlorine molecule on the basis of electronic theory of valency.


Explain why, diamond is hard while graphite is soft (though both are made of carbon atoms).

 

Draw the electron-dot structure of NHand state the type of bonding. 


Give the formulae of the chlorides of the elements X and Y having atomic numbers of 3 and 6 respectively. Will the properties of the two chlorides be similar or different? Explain your answer.


Give examples for the following:
Two solid covalent compounds.


Draw the electron dot diagram and structure of magnesium chloride.


Identify the incorrect statement and correct them.

  1. Like covalent compounds, coordinate compounds also contain charged particles (ions). So they are good conductors of electricity. 
  2. Ionic bond is a weak bond when compared to Hydrogen bond.
  3. Ionic or electrovalent bonds are formed by mutual sharing of electrons between atoms. 
  4. Loss of electrons is called Oxidation and gain of electron is called Reduction.
  5. The electrons which are not involved in bonding are called valence electrons.

Which of the following are correct structural isomers of butane?

  1. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\phantom{....}|\phantom{....}|\\
    \ce{H - C - C - C - C - H}\\
    |\phantom{....}|\phantom{....}|\phantom{....}|\\
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    \end{array}\]

  2. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\phantom{....}|\\
    \ce{H - C - C - C - H}\\
    |\phantom{.....}|\phantom{.....}|\\
    \ce{H}\ce{H-C-H}\ce{H}\\
    |\\
    \ce{H}\\
    \end{array}\]
  3. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\phantom{....}|\\
    \ce{H - C - C - C - H}\\
    |\phantom{.....}\backslash\phantom{..}|\\
    \phantom{....}\ce{H}\phantom{......}\ce{C - H}\phantom{}\\
    \phantom{.......}|\\
    \phantom{.......}\ce{H}\\
    \end{array}\]
  4. \[\begin{array}{cc}
    \ce{H}\phantom{...}\ce{H}\\
    |\phantom{....}|\\
    \ce{H - C - C - H}\\
    |\phantom{....}|\\
    \ce{H - C - C - H}\\
    |\phantom{....}|\\
    \ce{H}\phantom{...}\ce{H}\\
    \end{array}\]

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