AO = BO
= 2.9 cm
Draw a line segment of given length and construct a perpendicular bisector to line segment using scale and compass
58 mm
58 mm = `58 xx 1/10` cm = 5.8 cm

Construction:
Step 1: Drawn a line. Marked two points A and B on it so that
AB = 5.8 cm = 58 mm.
Step 2: Using compass with A as centre and radius more than half of the length of AB, drawn two arcs of the same length one above AB and one below AB.
Step 3: With the same radius and B as centre drawn two arcs to cut the arcs of drawn in step 2.
Marked the points of intersection of the arcs as C and D.
Step 4: Joined C and D. CD intersects AB. Marked the point of intersection as O.
CD is the required perpendicular bisector.
∠AOC = 90°
AO = BO
= 2.9 cm
Only one perpendicular bisector can be drawn to a given line segment.
Infinitely many perpendiculars can be drawn to a given ray.
In the following figure, the point C is the image of point A in line l and line segment BC intersects the line l at P.

Draw a line segment of length 7 cm. Draw its perpendicular bisector, using ruler and compasses.
Copy figure on your notebook and draw a perpendicular to l through P, using (i) set squares (ii) protractor (iii) ruler and compass. How many such perpendiculars are you able to draw?

Draw a line segment of length 12.8 cm. Using compasses, divide it into four equal parts. Verify by actual measurement.
With `overline"PQ"` of length 6.1 cm as diameter, draw a circle.
Draw a circle with centre C and radius 3.4 cm. Draw any chord `overline"AB"`. Construct the perpendicular bisector of `overline"AB"` and examine if it passes through C.
Repeat Question 6, if `overline"AB"` happens to be a diameter.
What property defines the Uniqueness of the perpendicular bisector?