Advertisements
Advertisements
प्रश्न
Find the acceleration due to gravity of the moon at a point 1000 km above the moon's surface. The mass of the moon is 7.4 × 1022 kg and its radius is 1740 km.
Advertisements
उत्तर
The acceleration due to gravity at a point at height h from the surface of the moon is given by \[g = \frac{GM}{r^2}\] ,
where M is the mass of the moon; r is the distance of point from the centre of the moon and G is universal gravitational constant.
\[\therefore g = \frac{GM}{\left( R + h \right)^2}\]
\[ \Rightarrow g = \frac{6 . 67 \times {10}^{- 11} \times 7 . 4 \times {10}^{22}}{\left( 1740 + 1000 \right)^2 \times {10}^6}\]
\[ \Rightarrow g = \frac{6 . 67 \times 7 . 4 \times {10}^{11}}{\left( 1740 + {1000}^2\times {10}^6 \right)}\]
\[ \Rightarrow g = \frac{6 . 67 \times 7 . 4 \times {10}^{11}}{2740 \times 2740 \times {10}^6}\]
\[ \Rightarrow g = 0 . 65 m/ s^2\]
APPEARS IN
संबंधित प्रश्न
Is there any meaning of “weight of the earth”?
The earth revolves round the sun because the sun attracts the earth. The sun also attracts the moon and this force is about twice as large as the attraction of the earth on the moon. Why does the moon not revolve round the sun? Or does it?
The acceleration of moon with respect to earth is 0⋅0027 m s−2 and the acceleration of an apple falling on earth' surface is about 10 m s−2. Assume that the radius of the moon is one fourth of the earth's radius. If the moon is stopped for an instant and then released, it will fall towards the earth. The initial acceleration of the moon towards the earth will be
The acceleration of the moon just before it strikes the earth in the previous question is
Suppose, the acceleration due to gravity at the earth's surface is 10 m s−2 and at the surface of Mars it is 4⋅0 m s−2. A 60 kg passenger goes from the earth to the Mars in a spaceship moving with a constant velocity. Neglect all other objects in the sky. Which part of the following figure best represents the weight (net gravitational force) of the passenger as a function of time?
Take the effect of bulging of earth and its rotation in account. Consider the following statements :
(A) There are points outside the earth where the value of g is equal to its value at the equator.
(B) There are points outside the earth where the value of g is equal to its value at the poles.
What is the acceleration due to gravity on the top of Mount Everest? Mount Everest is the highest mountain peak of the world at the height of 8848 m. The value at sea level is 9.80 m s−2.
A body is weighed by a spring balance to be 1.000 kg at the North Pole. How much will it weigh at the equator? Account for the earth's rotation only.
A particle is fired vertically upward from earth's surface and it goes up to a maximum height of 6400 km. Find the initial speed of particle.
A mass of 6 × 1024 kg (equal to the mass of the earth) is to be compressed in a sphere in such a way that the escape velocity from its surface is 3 × 108 m s−1. What should be the radius of the sphere?
If the acceleration due to gravity becomes 4 times its original value, then escape speed ____________.
If both the mass and the radius of the earth decrease by 1%, then the value of acceleration due to gravity will
One can easily weigh the earth by calculating the mass of the earth by using the formula:
A person whose mass is 100 kg travels from Earth to Mars in a spaceship. Neglect all other objects in the sky and take acceleration due to gravity on the surface of the Earth and Mars as 10 m/s2 and 4 m/s2 respectively. Identify from the below figures, the curve that fits best for the weight of the passenger as a function of time.
If R is the radius of the earth and g is the acceleration due to gravity on the earth's surface, the mean density of the earth is ______.
A ball is immersed in water kept in container and released. At the same time container is accelerated in horizontal direction with acceleration, `sqrt44` m/s2. Acceleration of ball w.r.t. container is ______ m/s2 (specific gravity of ball = 12/17, g = 10 m/s2)
