Advertisements
Advertisements
प्रश्न
Discuss in brief about the properties of coordinate covalent compounds.
संक्षेप में उत्तर
Advertisements
उत्तर
- Physical state – These compounds exist as gases, liquids or solids.
- Electrical conductivity – Like covalent compounds, coordinate compounds also do not contain charged particles (ions), so they are bad conductors of electricity.
- Melting point – These compounds have melting and boiling points higher than those of purely covalent compounds but lower than those of purely Ionic compounds.
- Solubility – Insoluble in polar solvents like water but are soluble in non-polar solvents like benzene, CCl4, and toluene.
- Reactions – Coordinate covalent compounds undergo molecular reactions which are
slow.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
APPEARS IN
संबंधित प्रश्न
Write structural formula of Methane.
How does graphite act as a lubricant?
What type of bond is present in the following molecule?
Cl2
Two atoms of the same element combine to form a molecule. The bond between them is known as ______ bond.
Draw the electron dot structure of the covalent compound methane (non polar) and HCl (polar) and give two difference between them.
The bond between two oxygen atoms is _______ bond.
Cation is formed when ______.
Which of the following are correct structural isomers of butane?
- \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - C - H}\\
|\phantom{....}|\phantom{....}|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{.....}|\phantom{.....}|\\
\ce{H}\ce{H-C-H}\ce{H}\\
|\\
\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\phantom{....}|\\
\ce{H - C - C - C - H}\\
|\phantom{.....}\backslash\phantom{..}|\\
\phantom{....}\ce{H}\phantom{......}\ce{C - H}\phantom{}\\
\phantom{.......}|\\
\phantom{.......}\ce{H}\\
\end{array}\] - \[\begin{array}{cc}
\ce{H}\phantom{...}\ce{H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H - C - C - H}\\
|\phantom{....}|\\
\ce{H}\phantom{...}\ce{H}\\
\end{array}\]
It is observed that covalent compounds are had conductors of electricity. Give reason.
Carbon can neither form C4- cation nor C4 anion. Why?
