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प्रश्न
Differentiate the following w. r. t. x. : `2/7 x^(7/2) + 5/2 x^(2/5)`
योग
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उत्तर
Let y =`2/7 x^(7/2) + 5/2 x^(2/5)`
Differentiating w.r.t. x, we get
`dy/dx = d/dx (2/7x^(7/2) + 5/2 x^(2/5))`
= `2/7d/dxx^(7/2) + 5/2 d/dxx^(2/5)`
= `2/7 xx7/2x^(7/2-1) + 5/2xx2/5 x^(2/5-1)`
= `x^(5/2) + x^((-3)/5)`
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