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प्रश्न
Differentiate the following w. r. t. x. : `x^(5/2) + 5x^(7/5)`
योग
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उत्तर
Let y = `x^(5/2) + 5x^(7/5)`
Differentiating w.r.t. x, we get
= `dy/dx = d/dx(x^(5/2) + 5x^(7/5))`
= `d/dx x^(5/2)+5d/dx x^(7/5)`
= `5/2x^(5/2-1) + 5 7/5x^(7/5-1)`
= `5/2x^(3/2) + 7x^(2/5)`
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