हिंदी

Differentiate 2^(cos^(2) x) w.r.t cos^2 x.

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प्रश्न

Differentiate `2^(cos^(2) x)` w.r.t cos2 x.

योग
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उत्तर

Let u = `2^(cos^(2) x)`

Differentiate w. r. t., x

`(du)/(dx) = 2^(cos^(2) x)log^2(-2 cos x sin x)`

`(du)/(dx) = -2 cos x sin x  2^(cos^(2) x)log 2`

and again let v = cos2 x

`(dv)/(dx) = -2 cos x sin x`

`(du)/(dx) = ((du)/(dx))/((dv)/(dx))`

= `(-2 cos x sin x  2^(cos^(2) x)log 2)/(-2 cos x sin x)`

∴ `(du)/(dv) = 2^(cos^(2) x)log 2`

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2024-2025 (March) Delhi Set 1
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