हिंदी

Diagram of the adjacent picture frame has outer dimensions = 24 cm × 28 cm and inner dimensions 16 cm × 20 cm. Find the area of each section of the frame, if the width of each section is same.

Advertisements
Advertisements

प्रश्न

Diagram of the adjacent picture frame has outer dimensions = 24 cm × 28 cm and inner dimensions 16 cm × 20 cm. Find the area of each section of the frame, if the width of each section is same.

योग
Advertisements

उत्तर

Area of ABFE

= `1/2` (AB + EF) × 4 cm2

= `1/2` (24 + 16) × 4 cm2

= `1/2` × 40 × 4 cm2

= 80 cm2

Also, Area of GHDC = Area of ABFE

= 80 cm2

Area of AEGC = `1/2` (EG + AC) × 4cm2

= `1/2 (20 + 28)` × 4cm2

= 96 cm2

Also, Area of AEGC = BFHD = 96 cm2 Area of EFHG

= HG × HF

= 16 × 20 cm2

= 320 cm2

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 9: Mensuration - EXERCISE 9.1 [पृष्ठ १०६]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 8
अध्याय 9 Mensuration
EXERCISE 9.1 | Q 11. | पृष्ठ १०६

वीडियो ट्यूटोरियलVIEW ALL [1]

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×