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Diagram of the adjacent picture frame has outer dimensions = 24 cm × 28 cm and inner dimensions 16 cm × 20 cm. Find the area of each section of the frame, if the width of each section is same. - Mathematics

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प्रश्न

Diagram of the adjacent picture frame has outer dimensions = 24 cm × 28 cm and inner dimensions 16 cm × 20 cm. Find the area of each section of the frame, if the width of each section is same.

योग
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उत्तर

Area of ABFE

= `1/2` (AB + EF) × 4 cm2

= `1/2` (24 + 16) × 4 cm2

= `1/2` × 40 × 4 cm2

= 80 cm2

Also, Area of GHDC = Area of ABFE

= 80 cm2

Area of AEGC = `1/2` (EG + AC) × 4cm2

= `1/2 (20 + 28)` × 4cm2

= 96 cm2

Also, Area of AEGC = BFHD = 96 cm2 Area of EFHG

= HG × HF

= 16 × 20 cm2

= 320 cm2

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अध्याय 9: Mensuration - EXERCISE 9.1 [पृष्ठ १०६]

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एनसीईआरटी Mathematics [English] Class 8
अध्याय 9 Mensuration
EXERCISE 9.1 | Q 11. | पृष्ठ १०६

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