Advertisements
Advertisements
प्रश्न
Determine whether the given values of x is the solution of the given quadratic equation below:
6x2 - x - 2 = 0; x = `(2)/(3), -1`.
Advertisements
उत्तर
6x2 - x - 2 = 0; x = `(2)/(3), -1`
Now put x = -1 in L.H.S. of equation.
L.H.S. = 6 x (-1)2 - (-1) -2
= 6 + 1 - 2
= 7 - 2 = 5 ≠ 0 ≠ R.H.S.
Hence, x = -1 is not a root of the equation.
Put x = `(2)/(3)` in L.H.S. of equation.
L.H.S. = 6 x `(2/3)^2 - (2)/(3) -2`
= `(24)/(9) - (2)/(3) - 2`
= `(8)/(3) - (2)/(3) - 2 = 0`
= 8 - 8 = 0
= R.H.S.
Hence, x = `(2)/(3)` is a solution of given equation.
संबंधित प्रश्न
Find the value of p for which the quadratic equation (2p + 1)x2 − (7p + 2)x + (7p − 3) = 0 has equal roots. Also find these roots.
Determine the nature of the roots of the following quadratic equation:
`3x^2-2sqrt6x+2=0`
Find the value of k for which the following equation has equal roots:
(k − 12)x2 + 2(k − 12)x + 2 = 0.
In each of the following, determine whether the given numbers are roots of the given equations or not; 3x2 – 13x – 10 = 0; 5, `(-2)/(3)`
Choose the correct answer from the given four options :
If the equation {k + 1)x² – 2(k – 1)x + 1 = 0 has equal roots, then the values of k are
If –5 is a root of the quadratic equation 2x2 + px – 15 = 0, then:
If x2 (a2 + b2) + 2x (ac + bd) + c2 +d2 = 0 has no real roots, then:
Find whether the following equation have real roots. If real roots exist, find them.
5x2 – 2x – 10 = 0
Find the value of ‘p’ for which the quadratic equation px(x – 2) + 6 = 0 has two equal real roots.
The roots of quadratic equation x2 – 1 = 0 are ______.
