हिंदी

Determine the order and degree of the following differential equations. Solution D.E. y = 1 − logx x2d2ydx2=1 - Mathematics and Statistics

Advertisements
Advertisements

प्रश्न

Determine the order and degree of the following differential equations.

Solution D.E.
y = 1 − logx `x^2(d^2y)/dx^2 = 1`
योग
Advertisements

उत्तर

y = 1 – log x

Differentiating w.r.t. x, we get

`dy/dx = -1/x`

Again, differentiating w.r.t. x, we get

`(d^2y)/dx^2 = 1/x^2`

∴ `x^2(d^2y)/dx^2 = 1`

∴  Given function is a solution of the given differential equation.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 8: Differential Equation and Applications - Exercise 8.1 [पृष्ठ १६२]

APPEARS IN

बालभारती Mathematics and Statistics 1 (Commerce) [English] Standard 12 Maharashtra State Board
अध्याय 8 Differential Equation and Applications
Exercise 8.1 | Q 2.4 | पृष्ठ १६२

संबंधित प्रश्न

\[\frac{d^2 y}{d x^2} + \left( \frac{dy}{dx} \right)^2 + xy = 0\]

For the following differential equation verify that the accompanying function is a solution:

Differential equation Function
\[x + y\frac{dy}{dx} = 0\]
\[y = \pm \sqrt{a^2 - x^2}\]

Differential equation \[\frac{d^2 y}{d x^2} + y = 0, y \left( 0 \right) = 0, y' \left( 0 \right) = 1\] Function y = sin x


(1 + x2) dy = xy dx


\[\frac{dy}{dx} = \frac{x e^x \log x + e^x}{x \cos y}\]

\[\frac{dy}{dx} = e^{x + y} + e^y x^3\]

\[y\sqrt{1 + x^2} + x\sqrt{1 + y^2}\frac{dy}{dx} = 0\]

tan y dx + sec2 y tan x dy = 0


Solve the following differential equation:
\[xy\frac{dy}{dx} = 1 + x + y + xy\]

 


\[2x\frac{dy}{dx} = 5y, y\left( 1 \right) = 1\]

Solve the differential equation \[\frac{dy}{dx} = \frac{2x\left( \log x + 1 \right)}{\sin y + y \cos y}\], given that y = 0, when x = 1.


Find the solution of the differential equation cos y dy + cos x sin y dx = 0 given that y = \[\frac{\pi}{2}\], when x = \[\frac{\pi}{2}\] 

 


\[\frac{dy}{dx} = \sec\left( x + y \right)\]

y ex/y dx = (xex/y + y) dy


Solve the following initial value problem:-

\[\frac{dy}{dx} + y\cot x = 2\cos x, y\left( \frac{\pi}{2} \right) = 0\]


Solve the following initial value problem:-

\[dy = \cos x\left( 2 - y\text{ cosec }x \right)dx\]


The rate of growth of a population is proportional to the number present. If the population of a city doubled in the past 25 years, and the present population is 100000, when will the city have a population of 500000?


In a simple circuit of resistance R, self inductance L and voltage E, the current `i` at any time `t` is given by L \[\frac{di}{dt}\]+ R i = E. If E is constant and initially no current passes through the circuit, prove that \[i = \frac{E}{R}\left\{ 1 - e^{- \left( R/L \right)t} \right\}.\]


Find the equation of the curve such that the portion of the x-axis cut off between the origin and the tangent at a point is twice the abscissa and which passes through the point (1, 2).


y2 dx + (x2 − xy + y2) dy = 0


Solve the differential equation:

`"x"("dy")/("dx")+"y"=3"x"^2-2`


Find the differential equation whose general solution is

x3 + y3 = 35ax.


y2 dx + (xy + x2)dy = 0


For the differential equation, find the particular solution (x – y2x) dx – (y + x2y) dy = 0 when x = 2, y = 0


Choose the correct alternative:

General solution of `y - x ("d"y)/("d"x)` = 0 is


A solution of differential equation which can be obtained from the general solution by giving particular values to the arbitrary constant is called ______ solution


The function y = ex is solution  ______ of differential equation


Given that `"dy"/"dx"` = yex and x = 0, y = e. Find the value of y when x = 1.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×