हिंदी

Determine the formula of the organic compound if its molecule contains 12 atoms of carbon. The percentage compositions of hydrogen and oxygen are 6.48 and 51.42 respectively.

Advertisements
Advertisements

प्रश्न

Determine the formula of the organic compound if its molecule contains 12 atoms of carbon. The percentage compositions of hydrogen and oxygen are 6.48 and 51.42 respectively.

संख्यात्मक
Advertisements

उत्तर

Element Percentage weight Atomic weight No. of moles Simple Ratio of atoms
H 6.48 1 `6.48/1` = 6.48 `48.6/3.21` = 2
O 51.42 16 `51.42/16` = 3.21 `3.21/3.21` = 1
C 42.1 12 `42.1/12` = 3.5 `3.5/3.21` = 1

The empirical formula is CH2O

Since the compound has 12 atoms of carbon, so the formula is

C12H24O12.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 5: Mole concept and Stoichiometry - EXERCISE-5C [पृष्ठ ९१]

APPEARS IN

एस पी सिंग Concise Chemistry [English] Class 10 ICSE
अध्याय 5 Mole concept and Stoichiometry
EXERCISE-5C | Q 20. | पृष्ठ ९१

संबंधित प्रश्न

The equation for the burning of octane is:

\[\ce{2C8H18 + 25O2 -> 16CO2 + 18H2O}\]

What is the empirical formula of octane?


On analysis, a substance was found to contain:

C = 54.54%, H = 9.09%, O = 36.36%

The vapour density of the substance is 44, calculate its empirical formula.


An organic compound, whose vapour density is 45, has the following percentage composition,

H = 2.22%, O = 71.19% and remaining carbon. Calculate its empirical formula.


10.47 g of a compound contained 6.25 g of metal A and rest non-metal B. Calculate the empirical formula of the compound [At. wt of A = 207, B = 35.5]


Find the empirical formula of a compound containing 17.64% hydrogen and 82.35% of nitrogen.


The percentage composition of sodium phosphate as determined by analysis is 42.1% sodium, 18.9% phosphorus and 39% oxygen. Find the empirical formula of the compound.


An experiment showed that in a lead chloride solution, 6.21 g of lead is combined with 4.26 g of chlorine. What is the empirical formula of this chlorine? (Pb = 207; Cl = 35.5)


The following experiment was performed in order to determine the formula of a hydrocarbon. The hydrocarbon X is purified by fractional distillation.

0.145 g of X was heated with dry copper (II) oxide and 224 cm3 of carbon dioxide was collected at S.T.P.

Calculate the empirical formula of X by the following step:

Calculate the number of moles of carbon dioxide gas.


The following experiment was performed in order to determine the formula of a hydrocarbon. The hydrocarbon X is purified by fractional distillation.

0.145 g of X was heated with dry copper (II) oxide and 224 cm3 of carbon dioxide was collected at S.T.P.

Calculate the empirical formula of X by the following step:

Calculate the mass of hydrogen in sample X.


The following experiment was performed in order to determine the formula of a hydrocarbon. The hydrocarbon X is purified by fractional distillation.

0.145 g of X was heated with dry copper (II) oxide and 224 cm3 of carbon dioxide was collected at S.T.P.

Calculate the empirical formula of X by the following step:

Deduce the ratio of atoms of each element in X (empirical formula).


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×