Question

Urea is a very important nitrogenous fertilizer. Its formula is CON₂H₄. Calculate the percentage of nitrogen in urea. (C = 12, O = 16, N = 14 and H = 1).

Answer 1

Molar mass of urea; CON₂H₄ = 60 g

Weight of nitrogen in 1 g-molecule of CON₂H₄ = 28 g

So, % of Nitrogen = `28/60 xx 100`

= 46.66%