Advertisements
Advertisements
प्रश्न
Determine the equation of a line passing through the point (−1, 2) with slope 4.
योग
Advertisements
उत्तर
Given values:
Point (x1, y1) = (−1, 2), Slope (m) = 4
Using the point–slope formula:
y − y1 = m(x − x1)
y − 2 = 4 [x − (−1)]
y − 2 = 4 (x + 1)
Let’s write the above equation in standard form (Ax + By + C = 0)
y − 2 = 4x + 4
0 = 4x − y + 4 + 2
∴ 4x − y + 6 = 0
Hence, the equation of a line is 4x − y + 6 = 0.
shaalaa.com
क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 12: Equation of a line - Exercise 12A [पृष्ठ २४५]
