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Deepa has a 4-year recurring deposit account in a bank and deposits Rs 1,800 per month. If she gets Rs 1,08,450 at the time of maturity, find the rate of interest. - Mathematics

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प्रश्न

Deepa has a 4-year recurring deposit account in a bank and deposits Rs 1,800 per month. If she gets Rs 1,08,450 at the time of maturity, find the rate of interest.

योग
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उत्तर

Installment per month (P) = Rs. 1,800

Number of months (n) = 48

Let rate of interest (r) = r% p.a.

∴ `S.I. = P xx (n(n + 1))/(2 xx 12) xx r/100`

= `1800 xx (48(48 + 1))/(2 xx 12) xx r/100`

= `1800 xx 2352/24  xx r/100`

= Rs. (1,764)r

Maturity value = Rs. (1,800 × 48) + Rs. (1,764)r

Given maturity value = Rs. 1,08,450

Then Rs. (1,800 × 48) + Rs. (1764)r = Rs. 1,08,450

`\implies` 1764r = Rs. 1,08,450 – Rs. 86,400

`\implies` r = `22050/1764` = 12.5%

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