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D∫x9(4x2+1)6 dx is equal to ______.

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प्रश्न

`int x^9/(4x^2 + 1)^6  "d"x` is equal to ______.

विकल्प

  • `1/(5x)(4 + 1/x^2)^-5 + "C"`

  • `1/5(4 + 1/x^2)^-5 + "C"`

  • `1/(10x)(1 + 4)^-5 + "C"`

  • `1/10(1/x^2 + 4)^-5 + "C"`

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उत्तर

`int x^9/(4x^2 + 1)^6  "d"x` is equal to `1/10(1/x^2 + 4)^-5 + "C"`.

Explanation:

Let I = `int x^9/(4x^2 + 1)^6 "d"x`

= `int  x^9/(x^12(4 + 1/x^2)^6) "d"x`

= `int 1/(x^3(4 + 1/x^2)^6) "d"x`

Put `(4 + 1/x^2)` = t

⇒ `(-2)/x^3 "dt"` = dt

⇒ `"dx"/x^3 = - 1/2 "dt"`

∴ I = `- 1/2 int "dt"/"t"^6`

= `- 1/2 xx - 1/5 "t"^-5 + "C"`

= `1/10 "t"^-5 + "C"`

= `1/10(4 + 1/x^2)^-5 + "C"`

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अध्याय 7: Integrals - Exercise [पृष्ठ १६७]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 7 Integrals
Exercise | Q 52 | पृष्ठ १६७

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