हिंदी

D∫cos2x-cos2θcosx-cosθdx is equal to ______.

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प्रश्न

`int (cos2x - cos 2theta)/(cosx - costheta) "d"x` is equal to ______.

विकल्प

  • 2(sinx + xcosθ) + C

  • 2(sinx – xcosθ) + C

  • 2(sinx + 2xcosθ) + C

  • 2(sinx – 2x cosθ) + C

MCQ
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उत्तर

`int (cos2x - cos 2theta)/(cosx - costheta) "d"x` is equal to 2(sinx + xcosθ) + C.

Explanation:

Let I = `int (cos2x - cos 2theta)/(cosx - costheta) "d"x`

= `int ((2cos^2x - 1 - 2 cos^2theta + 1))/(cosx - costheta) "d"x`

= `2int ((cosx + cos theta)(cosx - costheta))/((cosx - costheta)) "d"x`

= `2int(cos x + cos theta) "d"x`

= 2(sinx + xcosθ) + C

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 7: Integrals - Exercise [पृष्ठ १६६]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 12
अध्याय 7 Integrals
Exercise | Q 48 | पृष्ठ १६६

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