Question

Convert to SI unit: 1J/g °F

Answer 1

1 J g⁻¹ °F⁻¹ = 1800 J kg⁻¹ K⁻¹ (or 1800 J kg⁻¹ °C⁻¹).

Since 1 g = 10⁻³ kg and a temperature interval of 1 °F = `5/9`°C = `5/9` K:

1 J g⁻¹ °F⁻¹ = `(1 J)/(10^-3 kg × 5/9 K)` = 1800 J kg⁻¹ K⁻¹