Question

Construct a triangle PQR with sides QR = 7 cm, PQ = 6 cm and \[\angle\]PQR = 60º. Then construct another triangle whose sides are \[\frac{3}{5}\] of the corresponiding sides of ∆PQR.

Answer 1

Steps of Construction
Step 1. Draw a line segment QR = 7 cm.
Step 2. At B, draw

\[\angle\]YQR.
Step 6. Along QY, mark five points R₁, R₂, R₃, R₄ and R₅ such that QR₁ = R₁R₂ = R₂R₃ = R₃R₄ = R₄R₅ .
Step 7. Join RR₅.
Step 8. From R₃, draw R₃R' || RR₅ meeting QR at R'.
Step 9. From R', draw P'R' || PR meeting PQ in P'.

Here, ∆P'QR' is the required triangle whose sides are \[\frac{3}{5}\] of the corresponding sides of ∆PQR.