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प्रश्न
Construct a triangle PQR with QR = 5.5 cm, ∠Q = 60° and angle R = 45°. Construct the circumcircle cif the triangle PQR.
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उत्तर
Steps of Construction:
(i) Draw a ∆PQR in which QR = 5.5 cm, ∠Q = 60° and ∠R = 45°.
(ii) Draw the arc bisector of PQ and PR which intersect at O.
(iii) Taking O as center and radius OP or OQ or OR draw a circle.
This circle will pass through vertices P, Q, and R.
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संबंधित प्रश्न
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The type of arc
| Type of circular arc | Name of circular arc | Measure of circular arc |
| Minor arc | ||
| Major arc |
Draw any circle and mark
- it's centre
- a radius
- a diameter
- a sector
- a segment
- a point in its interior
- a point in its exterior
- an arc
