Advertisements
Advertisements
प्रश्न
Construct a triangle ABC in which BC = 5 cm, ∠B = 60° and AC + AB = 7.5 cm.
Advertisements
उत्तर
Given, in ΔABC, BC = 5 cm, ∠B = 60° and AC + AB = 7.5 cm.
To construct the triangle ABC use the following steps:
- Draw the base BC = 5 cm.
- At the point B make an ∠XBC = 60°.
- Cut a line segment BD equal to AB + AC = 7.5 cm from the ray BX.

- Join DC.
- Make an ∠DCY = ∠BDC.
- Let CY intersect BX at A.
Then, ΔABC is the required triangle.
APPEARS IN
संबंधित प्रश्न
Construct a triangle ABC in which BC = 7 cm, ∠B = 75° and AB + AC = 13 cm.
Construct a triangle PQR in which QR = 6 cm, ∠Q = 60° and PR − PQ = 2 cm
Construct a ΔABC in which BC = 3.6 cm, AB + AC = 4.8 cm and ∠B = 60°.
Using ruler and compasses only, construct a ΔABC, given base BC = 7cm, ∠ABC = 60° and AB + AC = 12 cm.
Construct a right triangle ABC whose base BC is 6 cm and the sum of hypotenuse AC and other side AB is 10 cm.
Construct a triangle ABC such that BC = 6 cm, AB = 6 cm and median AD = 4 cm.
The construction of a triangle ABC, given that BC = 6 cm, ∠B = 45° is not possible when difference of AB and AC is equal to ______.
An angle of 52.5° can be constructed.
A triangle ABC can be constructed in which AB = 5 cm, ∠A = 45° and BC + AC = 5 cm.
Construct the following and give justification:
A right triangle when one side is 3.5 cm and sum of other sides and the hypotenuse is 5.5 cm.
