हिंदी

Complete the following activity to find the 19th term of an A.P. 7, 13, 19, 25, ........ : Activity: Given A.P. : 7, 13, 19, 25, .......... Here first term a = 7; t19 = ?

Advertisements
Advertisements

प्रश्न

Complete the following activity to find the 19th term of an A.P. 7, 13, 19, 25, ........ :

Activity: 

Given A.P. : 7, 13, 19, 25, ..........

Here first term a = 7; t19 = ?

tn + a + `(square)`d .........(formula)

∴ t19 = 7 + (19 – 1) `square`

∴ t19 = 7 + `square`

∴ t19 = `square`

रिक्त स्थान भरें
योग
Advertisements

उत्तर

Given, A.P. : 7, 13, 19, 25, ..........

Here, first term a = 7; t19 = ?

tn + a + (n  – 1)d .........(formula)

∴ t19 = 7 + (19 – 1)6

∴ t19 = 7 + 108

∴ t19 = 115

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
2021-2022 (March) Set 1

APPEARS IN

संबंधित प्रश्न

How many multiples of 4 lie between 10 and 250?


In an AP given a3 = 15, S10 = 125, find d and a10.


Find the sum of first 12 natural numbers each of which is a multiple of 7.


Find the middle term of the AP 6, 13, 20, ..., 216.


The 4th term of an AP is 11. The sum of the 5th and 7th terms of this AP is 34. Find its common difference.


Divide 24 in three parts such that they are in AP and their product is 440.


The sum of three consecutive terms of an AP is 21 and the sum of the squares of these terms is 165. Find these terms.


Write an A.P. whose first term is a and common difference is d in the following.

a = –19, d = –4


In an A.P. the 10th term is 46 sum of the 5th and 7th term is 52. Find the A.P.


If first term of an A.P. is a, second term is b and last term is c, then show that sum of all terms is  \[\frac{\left( a + c \right) \left( b + c - 2a \right)}{2\left( b - a \right)}\].


The sum of 5th and 9th terms of an A.P. is 30. If its 25th term is three times its 8th term, find the A.P.


If the sum of a certain number of terms starting from first term of an A.P. is 25, 22, 19, ..., is 116. Find the last term.


Find the sum  (−5) + (−8)+ (−11) + ... + (−230) .


The number of terms of the A.P. 3, 7, 11, 15, ... to be taken so that the sum is 406 is


The sum of the first 15 multiples of 8 is ______.


In an AP if a = 1, an = 20 and Sn = 399, then n is ______.


In an A.P., if Sn = n(4n + 1), find the A.P.


The sum of n terms of an A.P. is 3n2. The second term of this A.P. is ______.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×