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Compare the chemistry of actinoids with that of the lanthanoids with special reference to chemical reactivity. - Chemistry

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प्रश्न

Compare the chemistry of actinoids with that of the lanthanoids with special reference to chemical reactivity.

अंतर स्पष्ट करें
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उत्तर १

Generally, the initial members of the series are very reactive like calcium in their chemical behaviour, but with increasing atomic number they behave like aluminium.

The value of EΘ for the half-reaction \[\ce{Ln^{3+}_{ (aq)} + 3e- -> Ln_{(s)}}\] is in the range of −2.2 V to −2.4 V. For Eu, the value of EΘ is −2.0 V. Of course, there is a slight variation in the value. These metals combine with hydrogen on being gently heated in an atmosphere of hydrogen gas. On heating these metals with carbon, the carbides Ln3C, Ln2C3 and LnC2 are formed. These metals liberate hydrogen gas from dilute acids and on burning in an atmosphere of halogens, form halides. These form oxide M2O3 and hydroxide M(OH)3. Hydroxides are definite compounds and not just hydrated oxides. They are basic, like the oxides and hydroxides of alkaline earth metals. Their general reactions are shown in the figure.

Actinoids are very reactive metals, especially when they are finely divided. The action of boiling water on them gives a mixture of oxide and hydride and combines with most non-metals at normal temperatures. Hydrochloric acid affects all metals, but most metals are little affected by nitric acid. The reason for this is that a protective surface of oxide is formed on these metals. Alkalis have no effect on these metals.

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उत्तर २

Actinoids are far more reactive than lanthanoids. They interact with nonmetals at moderate temperatures. In contrast, lanthanoids react at high temperatures. The majority of actinoids are attacked by HNO3 has a small effect on HCl, although the creation of a protective layer of oxide. Alkalies cause no reaction. Lanthanoids extract hydrogen from dilute. Acids and halogens burn together to generate halides. 

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अध्याय 4: The d-block and f-block Elements - Exercises [पृष्ठ ११७]

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नूतन Chemistry Part 1 and 2 [English] Class 12 ISC
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संबंधित प्रश्न

What are chemical twins? Write ‘two’ examples.


Which among the following pairs of elements is 'not' an example of chemical twins?


Compare the chemistry of actinoids with that of the lanthanoids with special reference to oxidation state.


The chemistry of the actinoid elements is not so smooth as that of the Lanthanoids. Justify this statement by giving some examples from the oxidation state of these elements.


Write the electronic configurations of the element with the atomic number 61.


The f-block elements are known as ____________.


Gadolinium belongs to 4f series. It’s atomic number is 64. Which of the following is the correct electronic configuration of gadolinium?


General electronic configuration of actinoids is `(n-2)f^(1-14)(n - 1)d^(0-2)ns^2`.Which of the following actinoids have one electron in 6d orbital?

(i) U (Atomic no. 92)

(ii) Np (Atomic no.93)

(iii) Pu (Atomic no. 94)

(iv) Am (Atomic no. 95)


Which of the following lanthanoids show +2 oxidation state besides the characteristic oxidation state +3 of lanthanoids?

(i) \[\ce{Ce}\]

(ii) \[\ce{Eu}\]

(iii) \[\ce{Yb}\]

(iv) \[\ce{Ho}\]


Although Zr belongs to 4d and Hf belongs to 5d transition series but it is quite difficult to separate them. Why?


Match the property given in Column I with the element given in Column II.

  Column I (Property) Column II (Element)
(i) Lanthanoid which shows
+4 oxidation state
(a) Pm
(ii) Lanthanoid which can show +2
oxidation state
(b) Ce
(iii) Radioactive lanthanoid (c) Lu
(iv) Lanthanoid which has 4f7
electronic configuration in +3
oxidation state
(d) Eu
(v) Lanthanoid which has 4f14
electronic configuration in
+3 oxidation state
(e) Gd
    (f) Dy

On the basis of Lanthanoid contraction, explain the following:

Nature of bonding in \[\ce{La2O3}\] and \[\ce{Lu2O3}\] .


On the basis of Lanthanoid contraction, explain the following:

Trends in the stability of oxo salts of lanthanoids from \[\ce{La}\] to \[\ce{Lu}\].


On the basis of Lanthanoid contraction, explain the following:

Radii of 4d and 5d block elements.


The titanium (Z = 22) compound that does not exist is:-


The lathanide ion that would show colour is ______.


Write a note on lanthanoids.


State a reason for the following:

La(OH)3 is more basic than Lu(OH)3.


Trivalent Lanthanoid ions such as La3+ (Z = 57) and Lu3+ (Z = 71) do not show any colour in their solution. Give a reason.


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