Advertisements
Advertisements
प्रश्न
Common factor of 17abc, 34ab2, 51a2b is ______.
विकल्प
17abc
17ab
17ac
17a2b2c
Advertisements
उत्तर
Common factor of 17abc, 34ab2, 51a2b is 17ab.
Explanation:
Given, 17abc = 17 × a × b × c
34ab2 = 2 × 17 × a × b × b
51a2b = 3 × 17 × a × a × b
Now, collecting the common factors, we get 17 × a × b = 17ab
APPEARS IN
संबंधित प्रश्न
Identify the numerical coefficient of term (other than constant) in the following expression:
5 − 3t2
Identify the term, their coefficients for the following expression:
\[\frac{a}{2} + \frac{b}{2} - ab\]
Simplify : 3m + 12m – 5m
Simplify: 7n2 – 9n2 + 3n2
Find the sum of: x3+3x2y and 2y2
Subtract the second expression from the first:
5a + b, - 6b + 2a
Subtract the second expression from the first:
4pq - 6p2 - 2q2 , 9p2
Find the numerical co-efficient of the following term:
12k
Factorise the following expression.
3pqr – 6p2q2r2 – 15r2
Number of terms in the expression 3x2y – 2y2z – z2x + 5 is ______.
