Advertisements
Advertisements
प्रश्न
Common factor of 17abc, 34ab2, 51a2b is ______.
पर्याय
17abc
17ab
17ac
17a2b2c
Advertisements
उत्तर
Common factor of 17abc, 34ab2, 51a2b is 17ab.
Explanation:
Given, 17abc = 17 × a × b × c
34ab2 = 2 × 17 × a × b × b
51a2b = 3 × 17 × a × a × b
Now, collecting the common factors, we get 17 × a × b = 17ab
APPEARS IN
संबंधित प्रश्न
Find the sum of: -2a and +5
Subtract the second expression from the first:
3a2 - 8ab - 2b2 , 3a2 - 4ab + 6b2
Subtract the second expression from the first:
10abc, 2a2 + 2abc - 4b2
Enclose the given term in bracket as required:
x2 -y2 + z2 + 3x – 2y = x2 – (……..)
Simplify: a + (b + c – d)
Simplify: 6a – 3 (a + b – 2)
To add two like terms, its coefficients can be added
The common factor method of factorisation for a polynomial is based on ______ property.
Write the greatest common factor in the following terms.
11x2, 12y2
Factors of –5x2y2z are ______.
