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प्रश्न
Common factor of 17abc, 34ab2, 51a2b is ______.
पर्याय
17abc
17ab
17ac
17a2b2c
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उत्तर
Common factor of 17abc, 34ab2, 51a2b is 17ab.
Explanation:
Given, 17abc = 17 × a × b × c
34ab2 = 2 × 17 × a × b × b
51a2b = 3 × 17 × a × a × b
Now, collecting the common factors, we get 17 × a × b = 17ab
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| Food Item (Per Unit = 100g) | Carbohydrates |
| Rajma | 60g |
| Cabbage | 5g |
| Potato | 22g |
| Carrot | 11g |
| Tomato | 4g |
| Apples | 14g |
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