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प्रश्न
\[\begin{array}{cc}
\ce{CH2 - CH2 ->[(A)] CH ≡ CH}\\
|\phantom{.......}|\phantom{.................}\\
\ce{Br}\phantom{.....}\ce{Br}\phantom{.................}
\end{array}\], where A is,
विकल्प
Zn
conc. H2SO4
alc. KOH
dil. H2SO4
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उत्तर
alc. KOH
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संबंधित प्रश्न
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