Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
`int sqrt((1 - x)/(1 + x)) "d"x` is
विकल्प
`sqrt(1 - x^2) + sin^-1x + "c"`
`sin^-1x - sqrt(1 - x^2) + "c"`
`log |x + sqrt(1 - x^2)| - sqrt(1 - x^2) + "c"`
`sqrt(1 - x^2) + log|x + sqrt(1 - x^2)| + "c"`
Advertisements
उत्तर
`sqrt(1 - x^2) + sin^-1x + "c"`
APPEARS IN
संबंधित प्रश्न
Integrate the following functions with respect to x :
`(sin^2x)/(1 + cosx)`
Integrate the following functions with respect to x :
cos 3x cos 2x
Integrate the following functions with respect to x :
`1/(sqrt(x + 3) - sqrt(x - 4))`
Integrate the following functions with respect to x :
`(x + 1)/((x + 2)(x + 3))`
Integrate the following with respect to x :
`x/sqrt(1 + x^2)`
Integrate the following with respect to x :
`("e"^x - "e"^-x)/("e"^x + "e"^-x)`
Integrate the following with respect to x :
`(sin sqrt(x))/sqrt(x)`
Integrate the following with respect to x :
`1/(x log x log (log x))`
Integrate the following with respect to x :
`tan x sqrt(sec x)`
Integrate the following with respect to x:
x3 sin x
Integrate the following with respect to x:
`sin^-1 ((2x)/(1 + x^2))`
Integrate the following with respect to x:
`"e"^x (tan x + log sec x)`
Find the integrals of the following:
`1/(6x - 7 - x^2)`
Integrate the following with respect to x:
`(2x + 1)/sqrt(9 + 4x - x^2)`
Choose the correct alternative:
`int tan^-1 sqrt((1 - cos 2x)/(1 + cos 2x)) "d"x` is
Choose the correct alternative:
`int (x^2 + cos^2x)/(x^2 + 1) "cosec"^2 x/("d"x)` is
Choose the correct alternative:
`int "e"^(- 4x) cos "d"x` is
Choose the correct alternative:
`int (sec^2x)/(tan^2 x - 1) "d"x`
Choose the correct alternative:
`int (x + 2)/sqrt(x^2 - 1) "d"x` is
