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Find the integrals of the following: 16x-7-x2

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प्रश्न

Find the integrals of the following:

`1/(6x - 7 - x^2)`

योग
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उत्तर

`int 1/(6x - 7 - x^2)  "d"x = int ("d"x)/(- 7 - x^2 + 6x)`

= `int ("d"x)/(- 7 - (x^2 - 6x))`

= `int ("d"x)/(- 7 - [(x - 3)^2 - 3^2]`

= `int ("d"x)/(- 7 - (x - 3)^2 + 9)`

= `int ("d"x)/(2 - (x - 3)^2`

= `int ("d"x)/((sqrt(2))^2 - (x - 3)^2)`

Put x – 3 = t, dx = dt

= `int "dt"/((sqrt(2)^2 - "t"^2)`

= `1/(2 xx (sqrt(2))) log |(sqrt(2) + "t")/(sqrt(2) - "t")| + "c"`

= `1/(2 xx sqrt(2)) log |(sqrt(2) + (x - 3))/(sqrt(2) - (x - 3))| + "c"`

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 11: Integral Calculus - Exercise 11.10 [पृष्ठ २१९]

APPEARS IN

सामाचीर कलवी Mathematics - Volume 1 and 2 [English] Class 11 TN Board
अध्याय 11 Integral Calculus
Exercise 11.10 | Q 2. (i) | पृष्ठ २१९

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