Advertisements
Advertisements
प्रश्न
Choose the correct alternative:
`int 1/(x sqrt(log x)^2 - 5) "d"x` is
विकल्प
`log |x + sqrt(x^2 - 5)| + "c"`
`log|log x + sqrt(log x - 5)| + "c"`
`log|log x + sqrt((log x)^2 - 5)| + "c"`
`log|log x - sqrt((log x)^2 - 5)| + "c"`
Advertisements
उत्तर
`log |log x + sqrt((log x)^2 - 5)| + "c"`
APPEARS IN
संबंधित प्रश्न
Evaluate : `int (1+logx)/(x(2+logx)(3+logx))dx`
Evaluate : `int_0^1 "x" . "tan"^-1 "x" "dx"`
Integrate the following functions with respect to x :
`(3 + 4cosx)/(sin^2x)`
Integrate the following functions with respect to x :
`(sin^2x)/(1 + cosx)`
Integrate the following with respect to x :
`("e"^x - "e"^-x)/("e"^x + "e"^-x)`
Integrate the following with respect to x :
`("cosec" x)/(log(tan x/2))`
Integrate the following with respect to x :
`(sin^-1 x)/sqrt(1 - x^2)`
Integrate the following with respect to x :
x(1 – x)17
Integrate the following with respect to x:
25xe–5x
Integrate the following with respect to x:
x log x
Integrate the following with respect to x:
x3 sin x
Integrate the following with respect to x:
`"e"^(2x) sinx`
Integrate the following with respect to x:
`(x + 2)/sqrt(x^2 - 1)`
Integrate the following functions with respect to x:
`sqrt(x^2 - 2x - 3)`
Integrate the following functions with respect to x:
`sqrt((x + 1)^2 - 4)`
Choose the correct alternative:
The gradient (slope) of a curve at any point (x, y) is `(x^2 - 4)/x^2`. If the curve passes through the point (2, 7), then the equation of the curve is
Choose the correct alternative:
`int ("e"^x(x^2 tan^-1x + tan^-1x + 1))/(x^2 + 1) "d"x` is
Choose the correct alternative:
`int "e"^(- 7x) sin 5x "d"x` is
Choose the correct alternative:
`int "e"^(sqrt(x)) "d"x` is
