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Can x2 – 1 be the quotient on division of x6 + 2x3 + x – 1 by a polynomial in x of degree 5?

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प्रश्न

Can x2 – 1 be the quotient on division of x6 + 2x3 + x – 1 by a polynomial in x of degree 5?

योग
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उत्तर

No, x2 – 1 cannot be the quotient on division of x6 + 2x3 + x – 1 by a polynomial in x of degree 5.

Justification:

When a degree 6 polynomial is divided by degree 5 polynomial,

The quotient will be of degree 1.

Assume that (x2 – 1) divides the degree 6 polynomial with and the quotient obtained is degree 5 polynomial (1)

According to our assumption,

(Degree 6 polynomial) = (x2 – 1)(Degree 5 polynomial) + r(x)  .....[Since, (a = bq + r)]

= (Degree 7 polynomial) + r(x)  ......[Since, (x2 term × x5 term = x7 term)]

= (Degree 7 polynomial)

From the above equation, it is clear that, our assumption is contradicted.

x2 – 1 cannot be the quotient on division of x6 + 2x3 + x – 1 by a polynomial in x of degree 5

Hence Proved.

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अध्याय 2: Polynomials - Exercise 2.2 [पृष्ठ ११]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 10
अध्याय 2 Polynomials
Exercise 2.2 | Q 1.(i) | पृष्ठ ११

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