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प्रश्न
Calculate the following:
A gas ‘X’ is collected over water at 17°C and 750 mm. pressure. If the volume of the gas collected is 50 cc., calculate the volume of the dry gas at s.t.p. [at 17°C the vapour pressure is 14 mm.]
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उत्तर
Initial conditions
T1 = 17 + 273 = 290 K
P1 = 750 mm - 14 mm
V1 = 50 c.c
Final conditions
T2 = 273 K
P2 = 760 mm
V2 = ?
Using gas equation `("P"_1"V"_1)/"T"_1 = ("P"_2"V"_2)/"T"_2`
∴ V2 = `("P"_1"V"_1"T"_2)/("T"_1"P"_2)`
`= (736 xx 50 xx 273)/(290 xx 760) = 45.58`
⇒ 45.6 cc
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संबंधित प्रश्न
State the law which is represented by the following graph:

Give reasons for the following:
It is necessary to specify the pressure and temperature of gas while stating its volume.
At constant temperature, the effect of change of pressure on the volume of a gas was as given below:
|
Pressure in atmosphere |
Volume in liters |
|
0.20 |
112 |
|
0.25 |
89.2 |
|
0.40 |
56.25 |
|
0.60 |
37.40 |
|
0.80 |
28.10 |
|
1.00 |
22.4 |
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(ii) graphical representation and
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