Question

Calculate the mass of sodium acetate (CH₃COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol^–1.

Answer 1

0.375 M aqueous solution of sodium acetate

≡ 1000 mL of solution containing 0.375 moles of sodium acetate

∴ Number of moles of sodium acetate in 500 mL

`=0.375/1000xx500`

= 0.1875 mole

Molar mass of sodium acetate = 82.0245 g mole^–1 (Given)

∴ Required mass of sodium acetate = (82.0245 g mol^–1) (0.1875 mole)

= 15.38 g