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कर्नाटक बोर्ड पी.यू.सी.पीयूसी विज्ञान 2nd PUC Class 12

Calculate and Compare the Energy Released by A) Fusion of 1.0 Kg of Hydrogen Deep Within Sun and B) the Fission of 1.0 Kg of 235u in a Fission Reactor.

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प्रश्न

Calculate and compare the energy released by a) fusion of 1.0 kg of hydrogen deep within Sun and b) the fission of 1.0 kg of 235U in a fission reactor.

संख्यात्मक
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उत्तर

(a) Amount of hydrogen, m = 1 kg = 1000 g

1 mole, i.e., 1 g of hydrogen `(""_1^1"H")`  contains 6.023 × 1023 atoms.

∴ 1000 g of `""_1^1"H"` contains 6.023 × 1023 × 1000 atoms.

Within the sun, four  `""_1^1"H"` nuclei combine and form one `""_2^4"He"` nucleus. In this process 26 MeV of energy is released.

Hence, the energy released from the fusion of 1 kg `""_1^1"H"` is:

`"E"_1 = (6.023 xx 10^23 xx 26 xx 10^3)/4`

`= 39.1495 xx 10^26 " MeV"`

(b) Amount of`""_92^235"U"` = 1 kg = 1000 g

1 mole, i.e., 235 g of  `""_92^235"U"` contains 6.023 × 1023 atoms.

∴ 1000 g of `""_92^235"U"` contains

`(6.023 xx 10^23 xx 1000)/235 "atmos"`

It is known that the amount of energy released in the fission of one atom of `""_92^235"U"` is 200 MeV.

Hence, energy released from the fission of 1 kg of `""_92^235"U"` is:

`"E"_2 = (6 xx 10^23 xx1000 xx 200)/235`

`= 5.106 xx 10^26 " MeV"`

`therefore "E"_1/"E"_1 = (39.1495 xx 10^26)/(5.106 xx 10^26) = 7.67 ~~ 8`

Therefore, the energy released in the fusion of 1 kg of hydrogen is nearly 8 times the energy released in the fission of 1 kg of uranium.

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अध्याय 13: Nuclei - Exercise [पृष्ठ ४६६]

APPEARS IN

एनसीईआरटी Physics Part I and II [English] Class 12
अध्याय 13 Nuclei
Exercise | Q 30 | पृष्ठ ४६६
एनसीईआरटी Physics Part I and II [English] Class 12
अध्याय 13 Nuclei
Exercise | Q 13.30 | पृष्ठ ४६६

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