हिंदी

By using ruler and compass only, construct a quadrilateral ABCD in which AB = 6.5 cm, AD = 2 cm and ∠DAB = 75°. C is equidistant from the sides AB and AD, also C is equidistant from the points A and - Mathematics

Advertisements
Advertisements

प्रश्न

By using ruler and compass only, construct a quadrilateral ABCD in which AB = 6.5 cm, AD = 2 cm and ∠DAB = 75°. C is equidistant from the sides AB and AD, also C is equidistant from the points A and B.

ज्यामितीय चित्र
दीर्घउत्तर
Advertisements

उत्तर

  • Draw a line segment AB = 6.5 cm.
  • At point A, construct an angle of 75°.
  • On this angle, mark AD = 2 cm and locate point D.
  • Draw the angle bisector of ∠DAB.
  • Draw the perpendicular bisector of AB.
  • The intersection of these two bisectors gives point C.
  • Join C to D and C to B to complete quadrilateral ABCD.

Since point C lies on the angle bisector of ∠DAB, it is equidistant from the sides AB and AD. Since point C lies on the perpendicular bisector of AB, it is equidistant from the points A and B. Therefore, quadrilateral ABCD is correctly constructed according to the given conditions.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 14: Locus - CHAPTER TEST [पृष्ठ ३०५]

APPEARS IN

नूतन Mathematics [English] Class 10 ICSE
अध्याय 14 Locus
CHAPTER TEST | Q 1. | पृष्ठ ३०५
Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×